Deep Blue Delay w/ Tails, Stomp Switch Wiring Question

[McSwainsWorld]

I have minimal knowledge about electronics but have been following a few builds on this site and haven't run into an issue until now. I can't figure out for the life of me how to wire the 3PDT switch in the Tails version of the Deep Blue Delay, since it's not standard. If it's not to much trouble, could someone draw up a diagram or explain how to do it? And does the build call for a separate ON/ON switch? If so would the instructions to wire Stomp 1 etc. actually mean to wire it to the ON/ON switch? Thanks, hope this makes sense.

[induction]

It's deceptively easy. The DPDT shown at the bottom of the layout is the stomp switch. (You can use a 3PDT if you want to, and just leave the 3rd pole unconnected. Technically, all you actually need is a 2PST on/off switch, the second throw is not used.)

1. Connect the wire marked 'Stomp 1' to lug 1 of the stomp switch.
2. Connect the wire marked 'Stomp 2' to lug 2 of the stomp switch.
3. Connect the LED cathode to lug 4 of the stomp switch.
4. Connect lug 5 of the stomp switch to ground.
Skip steps 3 and 4 if you don't want an led.

That's it.


More explanation, if you're interested:
This circuit mixes the dry signal together with the delayed signal. The dry signal goes from the input jack, through the input buffer, through the output mixer, to the output jack. This happens whether the pedal is engaged or not. To engage the pedal, the dry signal is not changed, but the signal from the input buffer is also connected to the delay chip input, and the delayed signal is sent to the output mixer to be blended with the dry signal. In other words, when the delay chip has an input signal you get echoes plus dry signal, when it doesn't you just get dry signal. The path from the input buffer to the delay chip input goes through the two wires marked 'Stomp 1' and 'Stomp 2'. Disconnecting those wires prevents the signal from reaching the delay chip. That's why you get tails. The chip stops getting input and stops making new repeats, but nothing prevents the existing repeats from reaching the output mixer.

It's actually much simpler than true bypass because we're just interrupting the signal in one place (one switch, connected or not), instead of rerouting the whole signal (two simultaneous switches, two possible connections for each switch).

This strategy works whenever the circuit mixes the bypass signal with the effected signal (reverbs and delays mostly), and requires buffered bypass.

[McSwainsWorld]

Thanks a lot! That really cleared things up.