I have added an led to a vox repeater. This flashes in time of the rate. So far so good. I just want it to be off when the effect is off, and I just can't seem to wrap my head around this. Even after extensive searching.
The Cathode is connected to B2 of the 2n2646 and the anode of the led with a resistor to 9v.
This will mean the led is always on ofcourse. There's always 9v going to the led, but since the anode of the led is not connected to the 3dpt switch (connecting and disconnecting it from ground) switching the effect on and off won't do anything.
What would be the correct way of doing / thinking?
Hope you've been doing ok! Thanks for taking the time to answer.
I think I get it :D
The Cathode will be always connected to the board, and the anode will not get any 9v when the switch is in the off position. Cause in the off position numbers 2 and 3 are connected.
By turning it on, a connection is made between lug 1 and 2, giving the led power.
I tried it and it works, awesome! The only difference is that the 9v is going directly to lug 2, and the anode goes with a resistor to lug 1. I had it attached to the led and didnt think it would matter. Correct me if i'm wrong!
Now I have a lot of ticking in bypass. If I connect lug 3 and 6 however, it gets a lot less (barely noticable).
I understand by doing that I am connecting the 9v going to lug 2 directly to ground when the switch is off. Would this cause any problems?
I will use this knowledge in a future build, thanks a lot. I have de/resoldered all the grounds, separated them etc so it looks like a warzone in there. Going to settle for a constant led (removed the ticking). It's for spacemen stuff, so with the depth all open, it's hard not to miss the tempo haha.